(Originais Teachy 2023) - Question Hard of Physics

A particle of charge q = 2.0 microcoulombs is released from rest in a uniform electric field created by two parallel electrically charged plates. The distance between the plates is d = 0.1 meters and the potential difference between them is V = 100 volts, with the positive plate on top. Considering negligible gravity, calculate the electric potential energy of the particle when it reaches the negative plate. Then, determine the velocity of the particle when it reaches the negative plate, assuming it does not interact with the electric field after passing through the positive plate. Consider the electric potential energy at the initial point as zero.