(Originais Teachy 2025) - Question Easy of Physics

A student is observing an object through a converging lens with a focal length of 10 cm. The object is located 40 cm away from the lens. (Consider that the thin lens approximation is valid). Based on this information: 1) Calculate the position of the image formed by the lens. 2) Determine the size of the image relative to the size of the object, knowing that the lens obeys the Gauss equation (1/f = 1/p + 1/p'), where f is the focal distance of the lens, p is the distance from the object to the lens, and p' is the distance from the image to the lens, all measured in cm. Consider that the coordinate system used has its origin at the lens's optical center, with the main axis oriented positively to the right, and that real images have a positive sign and virtual images have a negative sign.

A solid object is fully submerged in a liquid with a density of 1200 kg/m³ at a depth of 8 metres. Given that the acceleration due to gravity is 9.81 m/s², let’s figure out how the pressure from the liquid on the object changes with depth and how this affects the total buoyant force acting on the object.

Which of the following statements is true about Faraday's Law?