(Originais Teachy 2023) - Question Medium of Physics

Two point charges, one negative of -5µC and the other positive of +3µC, are fixed at points A and B, respectively, at a distance of 20 cm from each other in a vacuum. An electron is placed at a point located 10 cm from the negative charge and on the same line connecting the charges, forming a right triangle with the charges. The electric field created by the positive charge at B is E_B = k*q_B/r_B², where k is the electrostatic constant in vacuum and q_B is the charge of B. Considering that the electric force on an electron is F = k*e*q/r², where e is the charge of the electron, determine: 1) The intensity of the electric force on the electron due to the positive charge at B. 2) The direction and sense of the resultant electric force acting on the electron. Disregard any effects of electric fields created by the negative charge A acting on the electron.